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Minim |
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level |
Description Gets the current level of the buffer. It is calculated as the root-mean-square of all the samples in the buffer.Signature float level() Returns float: the RMS amplitude of the buffer Related AudioBufferExample /**
* This sketch demonstrates how to use the AudioBuffer objects of an AudioPlayer
* to draw the waveform and level of the sound as it is playing. These same
* AudioBuffer objects are available on AudioInput, AudioOuput, and AudioSample,
* so they same drawing code will work in those cases.
*
*/
import ddf.minim.*;
Minim minim;
AudioPlayer groove;
void setup()
{
size(1024, 200);
minim = new Minim(this);
groove = minim.loadFile("groove.mp3", 1024);
groove.loop();
}
void draw()
{
background(0);
stroke( 255 );
// draw the waveforms
// the values returned by left.get() and right.get() will be between -1 and 1,
// so we need to scale them up to see the waveform
// note that if the file is MONO, left.get() and right.get() will return the same value
for(int i = 0; i < groove.bufferSize() - 1; i++)
{
float x1 = map( i, 0, groove.bufferSize(), 0, width );
float x2 = map( i+1, 0, groove.bufferSize(), 0, width );
line( x1, 50 + groove.left.get(i)*50, x2, 50 + groove.left.get(i+1)*50 );
line( x1, 150 + groove.right.get(i)*50, x2, 150 + groove.right.get(i+1)*50 );
}
noStroke();
fill( 255, 128 );
// the value returned by the level method is the RMS (root-mean-square)
// value of the current buffer of audio.
// see: http://en.wikipedia.org/wiki/Root_mean_square
rect( 0, 0, groove.left.level()*width, 100 );
rect( 0, 100, groove.right.level()*width, 100 );
}
Usage Web & Application |